factories 1/27x3-1/216y3
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(1/3x)^3 - (1/6y)^3
by identity
a^3-b^3
= (a-b)(a^2+ab +b^2)
so
(1/3x - 1/6y)(1/9x^2 + 1/18xy +36y^2)
shadowsabers03:
I think it can be further factorized again.
This answer is wrong
Please mark my answer as a brainliest answer
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