Math, asked by annasandrasamson, 7 months ago

factories 27.x^3-(3 x-y)^3

Answers

Answered by Hɾιтհιĸ

30

(3x)^3-(3x-y)^3

= [3x-(3x-y)][(3x)^2+3x(3x-y)+(3x-y)^2]

=(3x-3x+y)[9x^2+9x^2-3xy+9x^2-6xy+y2]

=(y)[27x^2-9xy+y^2]

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