Question

factories 27y3+125z3

Answer 1

hey
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(27y)whole cube +(125z) whole cube

using the identity

a cube + b cube = (a+b)(a^2 -ab+b^2)

(3y) ^3 + (5z)^3

(3y+5z) (3^2y - 3y*5z+ 5^2z)

(3y+5z) (9y^2 -15yz +25z^2)

hope helped
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Answer 2

Answer :


$given \: expression \: = \\ \\ = > \: 27 {y}^{3} + {125z}^{3} \\ \\ = > \: as \: we \: know \: that \\ \\ \: = > \: {3}^{3} = 27 \\ \\ = > \: {5}^{3} = 125 \\ \\ = > \: so \: given \: expression \: can \: be \: written \: as \\ \\ = > \: ({3y)}^{3} + ( {5z)}^{3} \\ \\ = > \: factorise \: the \: expression \\ \\ = > \: by \: using \: the \: identity \: \\ \\ = \: {a}^{ 3} + {b}^{3} = (a + b)(a {}^{2} - ab + b {}^{2} ) \\ \\ = > \: (3y + 5z)(( {3y})^{2} - 3y \times 5z + (5z) {}^{2} ) \\ \\ = >( 3y + 5z)( {9y}^{2} - 15yz + 25z {}^{2} )$


Hope it would help you