Question

Factories 2xsquare+7x+3

Answer 1

Answer:

2x²+7x+3

= 2x²+6x+x+3

= 2x(x+3)+1(x+3)

= (x+3)(2x+1)

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Answer 2

Step-by-step explanation:

2x² + 7x + 3

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)So,

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)So,2x + 1 = 0.

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)So,2x + 1 = 0.x = -½

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)So,2x + 1 = 0.x = -½And,

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)So,2x + 1 = 0.x = -½And,x + 3 = 0

2x² + 7x + 3( 3*2 = 6 and factors of 6 are : 1,2,3,6, . So we take 6 and 1 )= 2x² + (6x + x) + 3=2x² + 6x + x + 3=2x ( x+3 ) + 1 ( x+3 )= ( 2x+1 ) ( x+3)So,2x + 1 = 0.x = -½And,x + 3 = 0x = - 3