Question

factories

32 a cube + 108 b cube

Answer 1

◢ WE KNOW THAT

=> (a³ + b³) = (a + b) (a² - ab + b²)

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◢ GIVEN,

=> 32a³ + 108b³

● take 4 common and factorise using (a³ + b³) formula

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◢ THEN,

$= > 32 {a}^{3} + 108 {b}^{3} \\ \\ = > 4(8 {a}^{3} + 27 {b}^{3} ) \\ \\ = > 4[( {2a})^{3} + ( {3b)}^{3} )] \\ \\ = > 4(2a + 3b)(4 {a}^{2} - 6ab + 9 {b}^{2} ) \: \: \: \: ......[Answer]$

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☆ $BE \: \: BRAINLY$ ☆