Question

Factories 4a2+12ab+9b2

Answer 1

Answer:

4a2+12ab+9b2 the final result is (2a-3b) power 2

Answer 2

Given equation,

$4a^{2} + 12ab + 9b^{2} =0$

SOMETHING YOU NEED TO KNOW

$1. (a+b)^{2} = a^{2} +2ab+b^{2} \\2. (a-b)^{2} = a^{2} -2ab + b^{2} \\3. (a-b)^{3} = (a-b)(a^{2} + ab + b^{2} )\\4. (a+b)^{3} = (a+b)(a^{2} - ab + b^{2} )$

$\implies 4a^{2} + 12ab+9b^{2} = 0 \\\implies (2a)^{2} + 2(2a)(3b) + (3b)^{2} = 0 \\\implies (2a+3b)^{2} = 0\\\implies (2a+3b)(2a+3b) = 0$

$\boxed{\boxed{\bold{Therefore, \ the \ factorised \ expression \ is \ (2a+3b)(2a+3b)}}}}$