Question

factories : 4y^2-2y^2-4y+2

Answer 1

$4 {y}^{2} - 2 {y}^{2} - 4y + 2 \\ 2 {y}^{2} - 4y + 2 \\ 2 {y}^{2} - 2y - 2y + 2 \\ 2y(y - 1) - 2(y - 1) \\ (2y - 2)(y - 1)$

Answer 2

Answer:

Step-by-step explanation:

4y^2-2y^2-4y+2=0

2y^2-4y+2=0

By factorization method

2y^2-2y-2y+2=0

2y (y-1) -2 (y-1)=0

(y-1) (2y-2)=0

(y-1)=0 or (2y-2)=0

y=1 or 2y =2

y=1 or y = 2/2

y=1 or y = 1

There value of y is 1 in both the cases