Math, asked by lalitkishore, 1 year ago

factories : 6x^2y^2(x^2-6x+8)÷(x-y)

if someone give this answer I'll mark his/her as brainlist and 5stars also​

Answers

Answered by Swarup1998
0

Solution:

Now, 6x²y² (x² - 6x + 8) / (x - y)

= 6x²y² (x² - 4x - 2x + 8) / (x - y)

= 6x²y² {x (x - 4) - 2 (x - 4)} / (x - y)

= 6x²y² (x - 4) (x - 2) / (x - y)

However, we reach at a step, after which what more can be done is indeterminate because like terms don't exist in numerator and denominatior.

Answered by ITZWildBoy
20

\huge\underline\mathfrak\purple{Answer}

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