Question

factories 7x^2 +2root 14 x+2

Answer 1

$7 {x}^{2} + 2 \sqrt{14} x + 2 \\ 7 {x}^{2} + \sqrt{14} x + \sqrt{14} x + 2 \\ \sqrt{7} \sqrt{7} {x}^{2} + \sqrt{2} \sqrt{7} x + \sqrt{2} \sqrt{7} x + \sqrt{2} \sqrt{2} \\ \sqrt{7}x ( \sqrt{7}x + \sqrt{2} ) + \sqrt{2} ( \sqrt{7} x + \sqrt{2} ) \\ ( \sqrt{7} x + \sqrt{2} )( \sqrt{7}x + \sqrt{2} ) \\ ( { \sqrt{7} x + \sqrt{2}) }^{2}$
to find the value of x,equate factors with zero
$\sqrt{7} x + \sqrt{2} = 0 \\ x = \frac{ - \sqrt{2} }{ \sqrt{7} } \\ x = \frac{ - \sqrt{2} \times \sqrt{7} }{ \sqrt{7} \times \sqrt{7} } \\x = \frac{ - \sqrt{14} }{7}$