Question

factories:7x+9√2x+4​

Answer 1

$7 {x}^{2} + 9 \sqrt{2} x + 4 \\ 7 {x}^{2} + 7\sqrt{2}x + 2 \sqrt{2}x + 4 \\ 7x(x + \sqrt{2} ) +2 \sqrt{2} (x + \sqrt{2} ) \\ (7x + 2 \sqrt{2} )(x + \sqrt{2} )$
$4 = 2 \times 2 \\ \sqrt{2} \times \sqrt{2} \times 2 = 4 \\ 2 \sqrt{2} ( \sqrt{2} ) = 4$

Answer 2

check ur question once again,

there will be 7x^2 instead of 7x

then , it's solution will be as:

7x^2+9√2x+4

7x^2+7√2x+2√2x+4

7x(x+√2)+2√2(x+√2)

(7x+2√2)(x+√2)

(7x+2√2)= 0 or x+√2=0

=> x =(-2√2)/7 or x= (-√2)

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