Question

Factories 8x^3 + √27 y^3 ?​

Answer 1

Answer:

Step-by-step explanation:

8x³+√27x³

= (2x)³ + (√3x)³

= (2x+√3x)(4x²-4√3x²+3x²)

= (2x+√3x)(12x²-4√3x²)

= 24x³-8√3x³+12√3x³-12x³

= 12x³+4√3x³

Answer 2

$we \: know \: the \: identity \\ {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab) \\ using \: the \: above \: identity \: the \: \\ equation \: can \: be \: factorise \: as \: follow \\ 8 {x}^{3} - 27 {y}^{3} = (2x {)}^{3} - (3y {)}^{3 = } \\ (2x - 3y)(2x {)}^{2} + (3y {)}^{2} + (2x \times 3y) \\ = (2x - 3y)(4 {x}^{2} + 9 {y}^{2} + 6xy) \: answer$