Question

factories a^3+b^3-a(a^2+b^2)+b(a+b)^2 by difference of two cube. the answer is b(a+b)(a+2b) tell me step by step explaination.​

Answer 1

Answer:

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Answer 2

I think the correct equation given is: a^3+b^3-a(a^2-b^2)+b(a+b)^2

STEPS:

first, let's open up the equation given to us

a^3+b^3-a(a^2-b^2)+b(a+b)^2

a^3+b^3-a(a^2-b^2)+b(a^2 + b^2 +2ab) [Applying the formula (A+B)^2 = A^2 + B^2 + 2AB on "(a+b)^2]

Now, opening all the brackets, we get,

a^3 + b^3- a^3 + ab^2 + ba^2 + b^3 +2ab^2 ......(1)

solving further,

2b^3 + 3ab^2 + ba^2

Now, Taking "b" common from all equations, we get,

b(2b^2 + 3ab + a^2)

splitting the middle term to get roots

b(2b^2 + 2ab + ab + a^2)

b(2b(b+a) + a(b+a))

Taking, "(b+a)" common,

b(b+a)(2b+a)

Answer is: b(b+a)(2b+a)

hope you get the solution now.

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