Question

Factories:
a(3a-2)-1​

Answer 1

Answer:

a(3a−2)−1=3a

2 −2a−1=3a

2−3a+a−1

=3a(a−1)+(a−1)

=(a−1)(3a+1)

Step-by-step explanation:

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Answer 2

Given:-

Factories:

a(3a-2)-1

Solution:-

${a(3a-2)-1}$

= ${3a^2}-{2a}-{1}$

= ${3a^2}-{3a}+{a}-{1}$

= ${3a(a-1)}+{(a-1)}$

= ${(a-1)}{(3a+1)}$