Question

Factories a2-b2-2bc-c

Answer 1

Answer:

Explaination:

Given : a2 −b 2+2bc−c2

We can write it as

a 2−b +2bc−c 2=a 2−(b 2−2bc+c 2)

We know that, (a−b) 2=a 2−2ab+b 2

a 2−(b 2−2bc+c 2)=a 2−(b−c) 2

Based on the identity, a 2−b 2=(a+

b)(a−b

We get,

a 2−(b−c) 2=[a+(b−c)[a−(b−c)]

⟹a 2−(b−c) 2=(a+b−c)(a−b+

c)

∴ a 2−b +2bc−c 2=(a+b−c)(a−

b+c)