Math, asked by hkhan15831, 9 months ago

Factories:a3-216 using suitable identity

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Answered by ananya4513
1

Answer:

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Answered by mehak238517
4

 

Factor a^3-216

a3−216a3-216

Rewrite 216216 as 6363.

a3−63a3-63

Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=(a-b)(a2+ab+b2) where a=aa=a and b=6b=6.

(a−6)(a2+a⋅6+62)

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