Math, asked by keerthanasre, 7 months ago

Factories by splitting a middle term 2b square +32b+128

Answers

Answered by sowmiyah86
1

Answer:

Equation at the end of step 1

(2b2 - 32b) + 128

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

2b2 - 32b + 128 = 2 • (b2 - 16b + 64)

Trying to factor by splitting the middle term

3.2 Factoring b2 - 16b + 64

The first term is, b2 its coefficient is 1 .

The middle term is, -16b its coefficient is -16 .

The last term, "the constant", is +64

Step-1 : Multiply the coefficient of the first term by the constant 1 • 64 = 64

Step-2 : Find two factors of 64 whose sum equals the coefficient of the middle term, which is -16 .

-64 + -1 = -65

-32 + -2 = -34

-16 + -4 = -20

-8 + -8 = -16 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and -8

b2 - 8b - 8b - 64

Step-4 : Add up the first 2 terms, pulling out like factors :

b • (b-8)

Add up the last 2 terms, pulling out common factors :

8 • (b-8)

Step-5 : Add up the four terms of step 4 :

(b-8) • (b-8)

Which is the desired factorization

Answered by heera39639
1

Answer:

2(b+8)(b+8)

Step-by-step explanation:

2b^2+32b+128

=2[(b)^2+2(b)(8)+(8)^2

=2[(b+8)^2]

=2(b+8)(b+8)

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