Question

factories it correctly otherwise I will report and correct answer will be marked as brainlist
$2 {x}^{2} - x + \frac{1}{8}$
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Answer 1

Given equation

$2x^{2} -x+\dfrac{1}{8} = 0$

Multiplying the equation by 8, we get,

$16x^{2} -8x+1=0$

Solving, we get,

$16x^{2} -8x+1=0$

$\implies 16x^{2} -4x-4x+1=0$

$\implies 4x(4x-1)-1(4x-1)=0$

$\implies (4x-1)(4x-1)=0$

$\boxed{\boxed{\bold{Therefore, \ the \ factorised \ expression \ is \ (4x-1)(4x-1)}}}}}}}}}$

                                                         

Answer 2

Answer:

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