Question

FACTORIES m^2+10m+25 using (a+b)^2 Identity​

Answer 1

Step-by-step explanation:

m^2+10m+25

= (m)^2+10m+(5)^2

= (m)^2+2*5*m+(5)^2

=(m+5)^2 or (m+5)(m+5)

Answer 2

$\huge\bold{\mathtt{Question⇒}}$

Factorise $m²+10m+25$ using $(a+b)²$ identity.

$\huge\bold{\mathtt{To\:find⇒}}$

The factor.

$\huge\bold{\mathtt{Solution⇒}}$

$m²+10m+25$

We can write:

• $10m$ as $(2×m×5)$

• $25²$ as $(5)²$

We know that:

$\large\boxed{(a+b)²=a²+2ab+b²}$

Here,

• $a = m$

• $b = 5$

$m²+10m+25$

$= m²+(2×m×5)+5²$

Use the formula of $(a+b)²$ and substitute $a$ with $m$ and $b$ with $5.$

$m²+(2×m×5)+5²$

$= (m+5)²$

$= (m+5)(m+5)$

$\huge\bold{\mathtt{Hence⇒}}$

$m²+10m+25 = (m+5)(m+5)$

$\huge\bold{\mathtt{Therefore⇒}}$

The factor of $m²+10m+25$ is $(m+5)(m+5).$

$\huge\bold{\mathtt{Done}}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

$\large\bold{\mathtt{Have\:a\:nice\:day.}}$