Question

factories the expressions l^2-161+64​

Answer 1

Answer:

$\red {Factors\:of\:the\: expression \:l^{2}-16l+64}$

$\green {=(l-8)(l-8)}$

Step-by-step explanation:

$\red {Given \: expression \:l^{2}-16l+64}$

$=l^{2}-2\times l\times 8 + 8^{2}$

$=(l-8)^{2}$

$=(l-8)(l-8)$

Therefore.,

$\red {Factors\:of\:the\: expression \:l^{2}-16l+64}$

$\green {=(l-8)(l-8)}$

••``

Answer 2

Answer:

l^2-16l+64=0

l^2-8l-8l+64=0

l(l-8)-8(l-8)=0

(l-8)(l-8)=0the values of l are 8,8

or

l^2-16l+64can written as a^2-2ab+b^2=(a-b)^2

so above equation can be written as (l-8)^2=0

l-8=0

l=8