Question

Factories the following

48x^3-27x

Answer 1

Hey! Here's your answer

48x^3 - 27x

= 3x (16x^2 - 9) -----------> Taking 3x common

= 3x ((4x)^2 - 3^2)

= 3x (4x + 3) (4x - 3) --------------> By identity a^2 - b^2 = (a + b)(a - b)

Hope this helps! :)

Answer 2

Hey dear friend

=>48x³-27x=0
=>3x(16x²-9)=0

=>3x=0
=>x=0

16x²-9=0
16x²=9
x²=9/16
x=3/4

So, the value of x can be 3/4 and 0

perfectly fine pure correct answer
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