Question

factories the following algebraic expressions(a) ax+bx_ay_by give me the answer​

Answer 1

Step-by-step explanation:

Given :-

ax+bx_ay_by

To find:-

Factorise the given expression

Solution:-

Method -1:-

Given expression is ax + bx -ay -by

=>(ax+bx)-(ay+by)

=>(a+b)x -(a+b)y

=>(a+b)(x-y)

ax + bx -ay -by = (a+b)(x-y)

Method-2:-

Given expression is ax + bx -ay -by

=>(ax-ay)+(bx-by)

=>a(x-y)+b(x-y)

=>(x-y)(a+b)

ax + bx -ay -by = (a+b)(x-y)

Answer:-

The factorization of the given expression is ax + bx -ay -by = (a+b)(x-y)