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(l+m)²-(l-m)²
using formula a²-b²=(a+b)(a-b)
therefore
a=(l+m)
b=(l-m)
then
(l+m+l-m){l+m-(l-m)}
2l(l+m-l+m)
2l×2m = 4lm
hope this helps
using formula a²-b²=(a+b)(a-b)
therefore
a=(l+m)
b=(l-m)
then
(l+m+l-m){l+m-(l-m)}
2l(l+m-l+m)
2l×2m = 4lm
hope this helps
Answered by
1
it is a^2-b^2
the answer will be[(l+m)+(l-m)][(l+m)-(l-m)]
the answer will be[(l+m)+(l-m)][(l+m)-(l-m)]
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