Factories x^4 - 125xy^3
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2
Given ,
x^4 - 125xy^3
= x(x^3 -125y^3 )
=x[ ( x - y ) ( x^2 +xy + y^2 )]
= x (x- y )(x^2 + xy + y^2 )
Thus factorized
manya1490:
Its ok
Answered by
0
Answer:
x^4 - 125xy^3
= x(x^3 -125y^3 )
=x[ ( x - y ) ( x^2 +xy + y^2 )]
= x (x- y )(x^2 + xy + y^2 )
Thus factorized
Step-by-step explanation:
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