Math, asked by laxmigupta33, 10 months ago

Factories' : x3 – x2y – xy2 + y3​

Answers

Answered by sonu7170
15

Answer:

I hope it will help you mate...............

Attachments:
Answered by sharonr
3

x^3-x^2y-xy^2+y^3 = (x-y)(x-y)(x+y)

Solution:

Given that,

x^3-x^2y-xy^2+y^3

We have to factorise the above expression

From given,

x^3-x^2y-xy^2+y^3

Group the expression

(x^3-x^2y)-(xy^2-y^3)

Take x square common from first group and y square common from second group

x^2(x-y) -y^2(x-y)

Take (x - y) as common

(x-y)(x^2-y^2)\\\\Expand\\\\(x-y)(x-y)(x+y)

Thus the given expression is factored

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