factories y^2-10y+25
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Answered by
1
Answer:
y2-5y-5y+25
y(y-5)-5(y-5)
(y-5)(y-5)
Answered by
5
Step-by-step explanation:
y²-10y+25
We have two ways to factorise it.the first way is through middle term splitting
y²-10y+25
=y²-5y-5y+25
=y(y-5)-5(y-5)
=(y-5)(y-5)
=(y-5)²
OR we can solve it through algebraic identity i.e. a²-2ab+b²=(a-b)²
y²-10y+25
=(y)²-2×y×5+(5)²
=(y-5)²
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