factoriez : 10x^2-29x+10
Answers
Answered by
0
Answer:
rst let's find the zeros of the polynomial by the quadratic formula:
x
=
−
29
±
√
29
2
−
4
⋅
10
⋅
10
2
⋅
10
=
−
29
±
√
441
20
=
−
29
±
21
20
x
1
=
−
29
−
21
20
=
−
5
2
x
2
=
−
29
+
21
20
=
−
2
5
Since
a
x
2
+
b
y
+
c
=
a
(
x
−
x
1
)
(
x
−
x
2
)
,
you get
10
x
2
+
29
x
+
10
=
10
(
x
+
5
2
)
(
x
+
2
5
)
=
2
⋅
(
x
+
5
2
)
⋅
5
⋅
(
x
+
2
5
)
=
(
2
x
+
5
)
(
5
x
+
2
)
Answered by
2
Answer:
hope this will help you
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