Question

factorisation. (3x^4-12x^2)÷(3x^3-6x^2)

Answer 1

$<b > hey here is your answer$

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$= \: \frac{3 {x}^{4} - 12 {x}^{2} }{3 {x}^{3} - 6 {x}^{2} } \\ \\ = \: \frac{3 {x}^{2} ( {x }^{2} - 4)}{3 {x}^{2}( x - 2)} \\ \\ = \: \frac{ {x}^{2} - 4}{x - 2} \\ \\ = \frac{ {x}^{2} - {2}^{2} }{x - 2}$

using identity

${a}^{2} - {b }^{2} = (a + b)(a - b)$

$= \frac{ {x}^{2} - {2}^{2} }{x - 2} \\ \\ = \frac{(x + 2)(x - 2)}{x - 2} \\ \\ = x + 2$

x+2 is the answer

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hope this helps you

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Answer 2

HEYA...THERE!!

YOUR SOLUTION...

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