Factorisation no. 2 with steps
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Solution :
4a² - 4b² + 4a + 1
= 4a² + 4a + 1 - 4b²
= [ (2a)² + 2×2a×1 + 1² ] - 4b²
= ( 2a + 1 )² - ( 2b )²
= ( 2a + 1 + 2b )( 2a + 1 - 2b )
•••••
4a² - 4b² + 4a + 1
= 4a² + 4a + 1 - 4b²
= [ (2a)² + 2×2a×1 + 1² ] - 4b²
= ( 2a + 1 )² - ( 2b )²
= ( 2a + 1 + 2b )( 2a + 1 - 2b )
•••••
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