Question

factorisation of
1/a²-64/b²
tell me step by step​

Answer 1

Answer:

(b + 8a)(b - 8a); where k = ab

Step-by-step explanation:

1/a^2 - 64/b^2

= (1/a)^2 - (8/b)^2

Using a^2 - b^2 = (a + b)(a - b) identity,

= (1/a + 8/b) (1/a - 8/b)

=k/ab(b + 8a)(b - 8a)

= (b + 8a)(b - 8a); where k = ab