Question

Factorisation of 28a3b5 - 48a5b3

Answer 1

Answer:

$28 {a}^{3} {b}^{5} - 48 {a}^{5} {b}^{3} = {2}^{2} \times 7 {a}^{3} {b}^{5} - {2}^{4} \times 3 {a}^{5} {b}^{3} = ( {2}^{2} {(ab)}^{3} )(7 {b}^{2} - 12 {a}^{2} )$

$= 4 {a}^{3} {b}^{3} (7 {b}^{2} - 12 {b}^{2} )$