Math, asked by daksh23, 1 year ago

factorisation of (2a+3b)²-16c²

Answers

Answered by Prernakumarisharma

(2a+3b)^2-16c
=> {(2a)^2+(3b)^2+2×2a×3b}- 16c
=> 4a^2+9b^2+12ab-16c
Hope it helps u!

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ajay103: ok by which way u did that sum i used the different formula and u another

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Answered by ajay103

we can take (2a+3b) as (x) and the reamaining 16c raise to the power 2 as (y) ok then apply the formula os a²-b² which is equal to( a+b) (a-b)
so (2a+3b+16c) (2a+3b-16c)

ajay103: have u got it

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daksh23: yaa ty

ajay103: what ty

ajay103: does it like that which u want

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