Question

factorisation of (2a+3b)²-16c²

Answer 1

(2a+3b)²-16c²

= (2a+3b)²-(4c)²

= using formula a²-b² = (a+b)(a-b)

= (2a+3b+4c)(2a+3b-4c)

hope this helps

Answer 2

Hi ,

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we know the algebraic identity ,

x² - y² = ( x + y ) ( x - y )

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( 2a + 3b )² - 16c²

= ( 2a + 3b )² - ( 4c )²

= ( 2a + 3b + 4c ) ( 2a + 3b - 4c )

I hope this helps you.

:)