mean of 50 b was found to be 80 but later on it was discovered that 96 was misread as a 69 find correct median
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♣ Mean and Median ♣
Here,
Sum of 50 observations = Mean * no. of observations
= 80.4 * 50
= 4020
Now, ATQ,
96 misread as 69.
So, new sum of observations:
= 4020 - 69 + 96
= 4020 + 27
= 4047
Now, New mean = sum of observations/ no. of observations
= 4047/50
= 80.94
Hence, the correct mean is 80.94.
♣ Mean and Median ♣
Here,
Sum of 50 observations = Mean * no. of observations
= 80.4 * 50
= 4020
Now, ATQ,
96 misread as 69.
So, new sum of observations:
= 4020 - 69 + 96
= 4020 + 27
= 4047
Now, New mean = sum of observations/ no. of observations
= 4047/50
= 80.94
Hence, the correct mean is 80.94.
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