Math, asked by josephannmariya47, 4 months ago

Factorisation of 4y²-8y+4 is ​

Answers

Answered by Anonymous
0

Answer:

4y square - 8y + 4

4y square -4y -4y + 4

( 4y square - 4y ) ( -4y + 4)

4y ( y - 1 ) -4 ( y - 1 )

( 4y -4) ( y -1)

4y - 4 = 0 or y - 1 = 0

4y = 4 y = 1

y = 4/4

y = 1

Step-by-step explanation:

hope its helps

Answered by Thenavi
0

Answer:

(y-1)(4y-4)

Step-by-step explanation:

4y²-8y+4

Product=4(4)=16

Sum= -8

4y²-8y+4=4y^2-4y-4y+4

=4y(y-1)-4(y-1)

=(y-1)(4y-4)

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