factorisation of p²-10p+21
Answers
Answered by
4
Answer:
7,3
Step-by-step explanation:
p^2-10p+21
p^2-7p-3p+(7)(3)
p(p-7)-3(p-7)
(p-7)(p-3)=0
p=7,3
Answered by
1
The factors where product is 21 and sum is -10 are -3,-7
p^2-3p-7p+21
p(p-3) - 7(p-3)
(p-7)(p-3)
p^2-3p-7p+21
p(p-3) - 7(p-3)
(p-7)(p-3)
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