Question

Factorisation of (pm + p) + m + 1

Answer 1

Answer:

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Answer 2

(m+1) (p+1)

We have (pm+p)+m+1

pm+p+m+1

p(m+1)+1(m+1) (p is common in first two terms )

(m+1) (p+1)  [taking m+1 common ]