Factorisation of (X+y) (2x+3y) - (x+y) (x+1)
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here is ur answer hope its clear to you
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we take (x+y) as a common factor
(x+y) (2x+3y)-(x+y)(x+1)
(x+y)[2x+3y-{x+1}]
(x+y)[2x+3y-x-1]
(x+y)(x+3y-1)
hope this helps you.....
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