factorisation of x2-6x+8
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x²-6x+8
x²-4x-2x+8
x(x-4)-2(x-4)
(x-4)(x-2)
x²-4x-2x+8
x(x-4)-2(x-4)
(x-4)(x-2)
Answered by
1
x^2 - 4x - 2x + 8 = 0
x ( x - 4 ) - 2 ( x - 4 ) = 0
( x - 2 ) ( x -4 ) = 0
x = 2, 4 ANSWER.
thanks...
x ( x - 4 ) - 2 ( x - 4 ) = 0
( x - 2 ) ( x -4 ) = 0
x = 2, 4 ANSWER.
thanks...
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