Question

factorisation of x2+x+14​

Answer 1

Answer:

x² + x + 14

Here,

a = 1

b = 1

c = 14

By quadratic formula,

x ₁ = $\frac{-b + \sqrt{D} }{2a}$              x ₂ = $\frac{-b - \sqrt{D} }{2a}$

D = b² - 4ac

D = 1² - 4 x (1) x (14)

D = 1 - 56

D = - 55 < 0

Therefore, No real roots

x ₁ = $\frac{-b + \sqrt{D} }{2a}$

x ₁ = $\frac{-1 + \sqrt{-55} }{2}$

x ₂ = $\frac{-b - \sqrt{D} }{2a}$

x ₂ = $\frac{-1 - \sqrt{\\-55} }{2}$

HOPE IT HELPS !!