Question

factorisation question 16a^2-144 solve

Answer 1

Here is your answer.....

= 16a²-144

It can also be written as
= (4a)²- (12)²

Now using identity ,

a²-b²= (a+b)(a-b)

where a= 4a
and b= 12
= (4a+12)(4a-12)
or taking out 4 as common
= 4(a+3)(a-3)

Hope this helps you.....✌^_^

Answer 2

We know that 4^2 =16

and 12^2 =144

16a^2-144

(4a)^2 - (12)^2

Now, using identity a^2 - b^2 = (a+b)(a-b)

=(4a+12)(4a-12)

Taking 4 common

=4(a+3)(a-3)

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Some identities

(a+b)^2 = a^2 +b^2 +2ab

(a-b)^2 = a^2 +b^2 -2ab

a^2-b^2 = (a+b)(a-b)