Math, asked by gaurav2496, 1 year ago

factorisation
$96 - 4x - x {}^{2}$

Answers

Answered by swarup007

0

$- {x}^{2} - 4x + 96 \\ - {x}^{2} - 12x \ \ + 8x + 96 \\ - x(x + 12) + 8(x + 12) \\ (x + 12)( - x + 8) = 0 \\ x = - 12 \: or \: x = 8$

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