Factorise
(0.4x+0.5y)(0.16x^2-0.4xy+0.25y^2)
Answers
Answered by
2
a^3+b^3=(a+b) (a^2-ab+b^2)
Simillarly,
0.4x+0.5y)(0.16x^2-0.4xy+0.25y^2)
=(0. 4x)^3+(0.5y)^3
=0.064x^3+0.125y^3
Simillarly,
0.4x+0.5y)(0.16x^2-0.4xy+0.25y^2)
=(0. 4x)^3+(0.5y)^3
=0.064x^3+0.125y^3
vanshika87919:
Sorry can u explain me a bit
Similar questions