Question

factorise 1 - 125 y^3

Answer 1

Answer:

1 - 125 y^3

= (1)^3 - (5y)^3

= (1-5y) [(1)^2+5y+(5y)^2]

= (1-5y) [1+5y+25y^2]

= hope it helps you

Answer 2

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$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

Factorise 1 - 125 y^3

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$\color{blue}\huge{\underline{\underline{\mathfrak{Answer}}}}$

${\blue{\bold{\text{ The factor will be }}}}$$\frac{1}{5}$

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$\color{orange}\huge{\underline{\underline{\mathfrak{Solution:-}}}}$

In the question we have to factorise 1-125y³

${\blue{\bold{ We\know\:that }}}$

125=5³

So, put 5³ at the place of 125

Now,

${\blue{\bold{Let\:1-5^{3}y^{3}=0 }}}$

${\blue{\bold{\text{ It can also be written as 1-(5y)^{3} }}}}$

So, 1-(5y)³=0

-(5y)³=-1

-(5y)³= cuberoot(-1)

-(5y)=-1 [Because (-1)³=-1 or cube root of -1 is -1]

(5y)=1

y=1/5

$\rule{200}3$

Hope it helps