Question

Factorise.
1. 24a cube+64y cube
answer should come 3(2a+3b)(4a square-6ab+9b square)
solve step by step ​

Answer 1

Answer:

${24a}^{3} + {81b}^{3} \\ = {2}^{3}3 {a}^{3} + {3}^{3} . {3} {b}^{3} \\ = {(2a)}^{3} 3 + 3{(3b)}^{3} \\ = 3({(2a)^{3} + {(3b)}^{3} }) \\ = 3(2a + 3b)(4 {a}^{2} - 6ab + 9 {b}^{2} )$

Step-by-step explanation:

hope that helps

Answer 2

24a •3 +81b •3

=23 3a •3 +3 •3 .3b• 3

=(2a) •3 3+3(3b)• 3

=3((2a) •3 +(3b)• 3 )

=3(2a+3b)(4a•2 −6ab+9b •2 )