question no.16 in the fig ab perpendicular to bc and de perpendicular to bc, ab=9 units , de=3 units and ac=25 units then ad is equal to
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AD = 50/3 Units if AB ⊥ BC and DE ⊥ BC, AB=9 units , DE=3 units and AC=25 units
Step-by-step explanation:
in ΔABC & ΔDEC
∠ABC = ∠DEC = 90°
∠C = ∠C ( common)
=> ΔABC ≈ ΔDEC
=> AB/ DE = AC/DC
=> 9/3 = 25/DC
=> DC = 25/3
AC = AD + DC
=> 25 = AD + 25/3
=> AD = 25 - 25/3
=> AD = 50/3 units
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