Factorise
1) 27x³+125y³+135x²y+225xy²
2) a³-8b³-64c³-24abc
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•27x³+125y³=(3x)³+(5y)³
By using formula,
a³+b³=(a+b)(a²-ab+b²)
=>(3x+5y)(9x²-15xy+25y²)
•a³-8b³-64c³-24abc
a³+(-2b)³+(-4c)³-3×a×(-2b)-4c
By using identinty,
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-2ab-2bc-2ca)
=>[a-2b-4c] [a²+(-2b)²+(-4c)²-2×a×(-2b) -2×(-2b)×-4c -2×a×(-4c)]
=>(a-2b-4c)(a²+4b²+16c²+4ab-8bc+8ac)
Hope it helps you ☺️,
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