factorise
1+2ab-(a^2+b^2)
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Answered by
2
-1-2ab+(a^2+b^2)
(a+b)^2-1
(a+b+1)(a+b-1)
(a+b)^2-1
(a+b+1)(a+b-1)
Answered by
1
1+2ab-(a"2+b"2)
=1 -(a"2+b"2-2ab)
=1- (a-b)"2
={1-(a-b)} {1+(a-b)}
=1 -(a"2+b"2-2ab)
=1- (a-b)"2
={1-(a-b)} {1+(a-b)}
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