Question

factorise
1. 3x +18x^2y-27
2.-64p^2q^2r + 72pqr
3.3a^3+3a-2a^2-2
4.5x(a-b)+6y(b-a)
5.m^4 -81n^4

please answer this

Answer 1

Hello Friend ✌
Here is u r Ans ➡

✨1 ➡
$= 3x + 18x {}^{2} y - 27$

$= 3(x + 6x { }^{2} y - 9)$

✨2 ➡
$= - 8pqr \times (8pq - 9)$


✨3 ➡
$= 3a {}^{} + 3a - 2a {}^{2} - 2$

$= 3a \times (a {}^{2} + ) - 2(a {}^{2} + 1)$

$= (a {}^{2} + 1)(3a - 2)$

✨4 ➡
$= 5x(a - b) + 6y \times (b - a)$

$= 5x \times (a - b) + 6y \times ( - (a - b))$

$= 5x \times (a - b) - 6y \times (a - b)$

$= (a - b) \times (5x - 6y)$

✨5 ➡
$= m {}^{4} - 81n {}^{4}$

$= using \: > \: a {}^{2} - b {}^{2} = (a - b)(a + b)$

$=( m {}^{2} - 9n {}^{2} ) \times (m {}^{2} + 9n {}^{2} )$

$= (m - 3n) \times (m + 3n) \times (m {}^{2} + 9n {}^{2} )$
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Answer 2

$1 ) 3x + 18x {}^{2} y - 27 =3x + 18x 2y−27  = 3 ( x + 6x { }^{2} y - 9 ) =3(x+6x2y−9)  2) - 8pqr \times (8pq - 9) =−8pqr × ( 8pq − 9 )  3 ) 3a {}^{} + 3a - 2a {}^{2} - 2 =3a+3a−2a2−2  = 3a \times (a {}^{2} + ) - 2(a {}^{2} + 1) =3a×(a2+)−2(a2+1)  = (a {}^{2} + 1)(3a - 2) =(a2+1)(3a−2)  4) 5x(a - b) + 6y \times (b - a)=5x(a−b)+6y×(b−a)  = 5x \times (a - b) + 6y \times ( - (a - b)) =5x×(a−b)+6y×(−(a−b))  = 5x \times (a - b) - 6y \times (a - b) =5x×(a−b)−6y×(a−b)  = (a - b) \times (5x - 6y) =(a−b)×(5x−6y)  5) m {}^{4} - 81n {}^{4}=m4−81n4  = using \: > \: a {}^{2} - b {}^{2} = (a - b)(a + b)=using>a2−b2=(a−b)(a+b)  =( m {}^{2} - 9n {}^{2} ) \times (m {}^{2} + 9n {}^{2} )=(m2−9n2)×(m2+9n2)  = (m - 3n) \times (m + 3n) \times (m {}^{2} + 9n {}^{2} )=(m−3n)×(m+3n)×(m2+9n2)$