Question

Factorise (1+3y)²+ (9y²-1)

Answer 1

Answer:

3y[1+3y]

Step-by-step explanation:

[1+3y]+[(3y)2[3y-1]

=(3y+1)(3y)

(3y+1) (3y)

=3y(3y+1)

so, 3y+(3y+1) is the answer..

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hope this helps u.....

Answer 2

Answer:

6y(3y+1)

Step-by-step explanation:

• (1+3y)²+ (9y²-1)=
• (1+3y)²+ (3y+1)(3y-1)=
• (3y+1)(3y+1+3y-1)=
• (3y+1)6y= 6y(3y+1)