Question

What is the area of a triangle with sides of length 2, 4, and 5?

Answer 1

Answer:

Step-by-step explanation:

According to Heron's formula:

s = a+b+c/2 = 2+4+5/2 = 11/2 = 5.5

Area = √s(s-a)(s-b)(s-c)

= √5.5(5.5-2)(5.5-4)(5.5-5)

= √5.5×3.5×1.5×0.5

= √55/10×35/10×15/10×5/10

= √5*11×5*7×5*3×5/10000

= 25/100√231

= 0.25√231